y^2-5/3y=25/28

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Solution for y^2-5/3y=25/28 equation: 


y in (-oo:+oo)

y^2-((5/3)*y) = 25/28 // - 25/28

y^2-((5/3)*y)-(25/28) = 0

y^2+(-5/3)*y-25/28 = 0

y^2-5/3*y-25/28 = 0

DELTA = (-5/3)^2-(-25/28*1*4)

DELTA = 400/63

DELTA > 0

y = ((400/63)^(1/2)+5/3)/(1*2) or y = (5/3-(400/63)^(1/2))/(1*2)

y = ((400/63)^(1/2)+5/3)/2 or y = (5/3-(400/63)^(1/2))/2

y in { (5/3-(400/63)^(1/2))/2, ((400/63)^(1/2)+5/3)/2 }

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